Monel metal is a corrosion-resistant copper-nickel alloy used in the electronics industry. A particular alloy with a density of 8.80 g/cm3 and containing 0.039 % Si by mass is used to make a rectangular plate that is 15.0 cm long, 12.5 cm wide, and 2.50 mm thick and has a 2.50-cm-diameter hole drilled through its center such that the height of the hole is 2.50 mm .The silicon in the plate is a mixture of naturally occurring isotopes. One of the those isotopes is silicon-30, which has an atomic mass of 29.97376 amu. The percent natural abundance, which refers to the atoms of a specific isotope, of silicon-30 is 3.10%.
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How many silicon-30 atoms are found in this plate?
Feb 2, 2018
This is going to be a bit long, so let"s quickly outline what we"re going to do to answer this question:Find the volume of the plate.Find the mass of the plate.Find the mass of silicon in the plate.Find the number of atoms of silicon. Find the number of atoms of silicon-30.
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Volume of Plate
First, to find the volume of the plate with the hole, find the volume of the plate without the hole.#V = lmh = "15cm" * "12.5cm" * "2.5mm" = "15cm" * "12.5cm" * "0.25cm" = 46.875 "cm"^3#(Let"s not worry about significant figures right now.)
Then, find the volume of the hole so we can subtract it from the volume of the plate. The plate probably looks like this:
With this information, we can use the formula for a cylinder"s volume to find the volume of this hole.
#V = pi r^2 h = pi * 1.25^2 * 0.25 = "1.2272 cm"^3#
Therefore, the volume of the plate with the hole in it is
#"original volume - hole volume" = 46.875 "cm"^3 - "1.2272 cm"^3 = "45.648 cm"^3#
Mass of PlateRemember the density formula?
#d = m/v#
We can rearrange that to input volume and density, and have it give us mass. We do this by multiplying the volume variable on both sides.
To find the mass of the plate, we"ll use this formula because we"ve been given the density
#m=d*v = "8.80g/cm"^3 * "45.648 cm"^3= "401.701g"#
Mass of Silicon in PlateThe question tells us that the alloy contains #0.039%# silicon by mass. This means that in every #"1g"#, there will be #"0.00039g"# of silicon. So, the mass of silicon in #"401.701g"# will be:
#0.00039 * "401.701g" = "0.157g"#
Atoms of Silicon#1# atom of silicon has an atomic mass of #"29.97376 amu"# (which has been given in the question), so that means #1# mole of silicon will have a mass of #"29.97376 g"#.
The number of moles of silicon in #"0.157g"# are:#"mass of sample"/"mass of 1 mole" = "0.157g" / "29.97376 g" = "0.005238 moles"#
We also know that there are #6.022*10^23# atoms in a mole, so that means there are #0.005238*6.022*10^23 = 3.154*10^21 "atoms"# in #"0.005238 moles"# of silicon.
Atoms of Silicon-30The question tells us that #3.10%# of silicon atoms are of the silicon-30 isotope. Assuming that this is also the case for our plate, the number of silicon-30 atoms will be:
#3.10% * 3.154*10^21 "atoms" = 0.031 * 3.154*10^21 "atoms" = 9.778*10^19 "atoms"#
The least amount of significant figures in the question is #3#, so our answer is going to have #3# significant figures: