rho g h two, this h two distinguishes it from h in part A. We now have actually 1.50 meter for the elevation now, minus push of the blood. I substituted the number one with a subscript b tright here to say that this is the blood pressure. Then we plug in numbers, so it's 1025 kilograms per cubic meter density, times 9.81 newloads per kilogram, times 1.5 meters, minus 1066.4 pascals which is eight millimeters of mercury converted right into pascals, then times pi, times 0.15 times ten to the minus three meters radius of the tube to the power four, divided by eight times the viscosity of 1.002 times ten to the minus three pascals secs, times two and also a half times ten to the minus 2 meters length of the tube. This functions out to 0.111 cubic centimeters per second after you convert this number which is in cubic meters per second by multiplying by 100 centimeters for every meter 3 times to gain right into units of cubic centimeters per second. Part C, the circulation will reverse once the push as a result of the elevation of the column of the saline solution amounts to the blood pressure. So we have actually rho g h for reversal, subscript r to suppose the height at which suggest the flow deserve to reverse, equates to blood pressure and we solve for h r by splitting both sides by rho g. So the elevation for reversal of the IV will certainly be 1066.4 pascals, separated by 1025 kilograms per cubic meter times 9.81 newloads per kilogram which is 0.106 meters which is 10.6 centimeters. So that suggests if a patient were to stand up and also the IV bag was less than 10.6 centimeters over their arm, then the IV drip wouldn't go into their arm anymore. So this is the write-up it's commonly on, some wheels right here, and also here's the bag via the saline solution in it and the hose connected to the needle in their arm. If this distance right here is ever before much less than 10.6 centimeters, favor if they lift their arm as much as their head say, then the IV drip won't work-related anymore.">

You are watching: An intravenous system is supplying saline solution

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This is College Physics Answers via Shaun Dychko. The intravenous device for this patient has a hose through a radius of 0.15 millimeters, which is 0.15 times ten to the minus 3 meters, and also the hose length is 2 and also a fifty percent centimeters. The blood push at the needle is eight millimeters of mercury which we convert right into pascals. The viscosity of the stuff in the IV tube, is the viscosity of water which is 1.002 times ten to the minus 3 pascal seconds. So the press due to the elevation of the liquid once it"s 1.61 meters over the needle is the thickness of the solution inside, it"s a saline solution so its density is 1025 kilograms per cubic meter, times 9.81 newtons per kilogram times the height in between the pouch and the needle in the person"s arm. So that"s 1.61 meters, in this instance 1.62 times ten to 4 pascals. Part B asks for what the price of the liquid circulation will certainly be through a height of 1.50 meters instead of the height provided to us in the example. So, the fluid circulation price will be the difference in the pressures, this is the press as a result of the height of the liquid and also this is going to be the blood press that"s pushing earlier on the liquid at the needle. So we take that press difference, multiply by pi times the radius of the IV tube to the power four, divided by eight times the viscosity of the saline solution, times the size of the tube. So, we have rho g h 2, this h 2 distinguishes it from h in part A. We currently have 1.50 meter for the height now, minus push of the blood. I substituted the number one through a submanuscript b tbelow to say that this is the blood push. Then we plug in numbers, so it"s 1025 kilograms per cubic meter density, times 9.81 newtons per kilogram, times 1.5 meters, minus 1066.4 pascals which is eight millimeters of mercury converted right into pascals, then times pi, times 0.15 times ten to the minus three meters radius of the tube to the power 4, split by eight times the viscosity of 1.002 times ten to the minus 3 pascals secs, times 2 and also a fifty percent times ten to the minus 2 meters length of the tube. This functions out to 0.111 cubic centimeters per second after you transform this number which is in cubic meters per second by multiplying by 100 centimeters for every meter three times to get into devices of cubic centimeters per second. Part C, the circulation will certainly reverse when the press as a result of the height of the column of the saline solution amounts to the blood pressure. So we have actually rho g h for reversal, submanuscript r to suppose the elevation at which allude the flow have the right to reverse, amounts to blood pressure and we fix for h r by separating both sides by rho g. So the elevation for reversal of the IV will certainly be 1066.4 pascals, split by 1025 kilograms per cubic meter times 9.81 newloads per kilogram which is 0.106 meters which is 10.6 centimeters. So that means if a patient were to stand also up and the IV bag was much less than 10.6 centimeters over their arm, then the IV drip wouldn"t go right into their arm anyeven more. So this is the write-up it"s usually on, some wheels below, and here"s the bag via the saline solution in it and also the hose linked to the needle in their arm. If this distance below is ever before much less than 10.6 centimeters, like if they lift their arm approximately their head say, then the IV drip will not occupational anyeven more. its really constantly the means you blow with a problem and also do not explain wbelow your derivations come from
Hi camdenreed, yeah, sorry if I was in a rush on that one. I attempt to discover a balance in between explaining thoroughly vs. not wasting students" time through overly verbose explanations. Sometimes that probably errs on the side of as well concise. If you have the right to form a certain question, I usually try to obtain back to students if time permits.

All the ideal,Shaun See more: A Cup Of Poetry — In And Out Of Time By Maya Angelou, In And Out Of Time, By Maya Angelou

It was my fault; I assumed a recognized equation was something you derived. Sorry, finals have actually me stressing haha.